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TRISECTION BY A CONE |
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On a
sheet of paper we have a circle O and radius R. An angle A is marked at
the centre of O. We have a circular sector of angle 120º=2p/3
and
radius 3R. The
cone that is formed with the sector is placed on the circle and with a
pencil we mark the two points that limit the given angle on the border
of the cone. If the cone is developed again, the centre of the sector
and the two points marked form an angle A/3, the trisection of the angle. |
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Why does this procedure work? |
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Solution | |
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